if we're hardening a macro to place within the die, can we just skip io placement? i'm getting errors about the number of pins that can fit around the permiter of the design, but i don't want it to matter

You can look at what I do in https://github.com/PyFive-RISC-V/pyfive_top_202011 I don't skip IO placement but in my macro I only fixed the pins that I actually use. Then I wire those to the right pin in the

user_project_wrapper

. Note that because inside the wrapper I don't have any standard cells, I cannot wire stuff to even

1

or

0

(because those use standard cells to output constans, the

conb

bloks) ... so I added ports in my macro that output constant signals so I wire unused stuff in the

wrapper

to them.

ok, i couldn't solve all my problems so i tried folding more of the logic into the child macros. now i'm trying to place 3 macros and 4 tie high/low cells. this is nightmarishly difficult for such a trivial task.

I don't have standard cell in the

user_project_wrapper

. I of course have cells in my

pyfive_top

block.

ok, i gotchu. my solution seems to be to re-run the flow until the initial seed places the 4 annoying cells somewhere not problematic