Luke Harold Miles
02/14/2024, 9:29 PMLuke Harold Miles
02/14/2024, 9:31 PMLuke Harold Miles
02/14/2024, 10:07 PMRyan Brandt
02/15/2024, 1:18 AMRyan Brandt
02/15/2024, 1:22 AMRyan Brandt
02/15/2024, 1:23 AMRyan Brandt
02/15/2024, 1:28 AMRyan Brandt
02/15/2024, 1:32 AMRyan Brandt
02/15/2024, 1:43 AMRyan Brandt
02/15/2024, 1:44 AMRyan Brandt
02/15/2024, 1:58 AMLuke Harold Miles
02/15/2024, 4:30 AMIs there a particular reason you're trying to multiply without having access to negative voltages?No reason! a_mid and b_mid can be zero. Thank you very much for the info and keywords. I was trying to do the expansion
(a-amid)*(b-bmid) = a*b - amid*b - bmid*a + amid*bmid
for quite a while but something was messed up that I couldn't figure out. I was doing something a bit different for that then what you described.
But with the right keywords and this other info I bet I can get it implemented.
And I hadn't considered exp-sum-log! I'll try that out too
You probably saved me like 3 days of work π»Ryan Brandt
02/15/2024, 5:03 AMLuke Harold Miles
02/15/2024, 5:10 AMThe requirement that the output be signed while the inputs are relative to a reference would seem to suggest using differential amplifiers for each input signal and then using a standard multiplier circuit.What kind of standard multiplier circuit would handle positive and negative input voltages?
Ryan Brandt
02/15/2024, 5:14 AMRyan Brandt
02/15/2024, 5:14 AMLuke Harold Miles
02/15/2024, 5:14 AMRyan Brandt
02/15/2024, 5:16 AMRyan Brandt
02/15/2024, 5:19 AMRyan Brandt
02/15/2024, 5:21 AMRyan Brandt
02/15/2024, 5:24 AMRyan Brandt
02/15/2024, 5:28 AMLuke Harold Miles
02/15/2024, 6:29 AMRyan Brandt
02/16/2024, 1:14 AM